24x^2+5x-36=0

Solution for 24x^2+5x-36=0 equation:

24x^2+5x-36=0

a = 24; b = 5; c = -36;
Δ = b2-4ac
Δ = 52-4·24·(-36)
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3481}=59$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-59}{2*24}=\frac{-64}{48}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+59}{2*24}=\frac{54}{48}
=1+1/8
$